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Ncert Solution For Class 9 Maths Chapter – 15

Ncert Solution For Class 9 Maths Chapter – 15 Probability provides a detailed understanding of fundamental probability concepts, tailored for the CBSE syllabus. This chapter includes step-by-step solutions to all exercises, helping students grasp key topics such as experimental probability and the calculation of chances related to random events. The solutions are crafted by experienced educators to ensure clarity and accuracy, making them an essential resource for exam preparation. Students can access these solutions in PDF format for offline study, enhancing their learning experience and confidence in tackling probability problems in exams

Here Are The Ncert Solution For Class 9 Maths Chapter – 15  Probability

Exercise 15.1

1. In a cricket match, a batswoman hits a boundary 6 times out of 30 balls she plays. Find the probability that she did not hit a boundary.

Solution:

According to the question,

Total number of balls = 30

Number of boundary = 6

Number of times batswoman didn’t hit boundary = 30 – 6 = 24

The probability she did not hit a boundary = 24/30 = 4/5

 

2. 1500 families with 2 children were selected randomly, and the following data were recorded:

Number of girls in a family 2 1 0
Number of families            475                     814                   211        

Compute the probability of a family, chosen at random, having

(i) 2 girls                (ii) 1 girl                   (iii) No girl
Also, check whether the sum of these probabilities is 1.

Solution:

Total number of families = 1500

(i) Number of families having 2 girls = 475

Probability = Number of families having 2 girls/Total number of families

= 475/1500 = 19/60

(ii) Number of families having 1 girl = 814

Probability = Number of families having 1 girl/Total number of families

= 814/1500 = 407/750

(iii) Number of families having 0 girls = 211

Probability = Number of families having 0 girls/Total number of families

= 211/1500

Sum of the probability = (19/60)+(407/750)+(211/1500)

= (475+814+211)/1500

= 1500/1500 = 1

Yes, the sum of these probabilities is 1.

3. Refer to Example 5, Section 14.4, Chapter 14. Find the probability that a student of the class was born in August.

Solution:

Ncert Solution For Class 9 Maths Chapter – 15 Probability

Total number of students in the class = 40

Number of students born in August = 6

The probability that a student of the class was born in August = 6/40 = 3/20

 

4. Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes:

Outcome              3 heads            2 heads          1 head          No head      
Frequency 23 72 77 28

If the three coins are simultaneously tossed again, compute the probability of 2 heads coming up.

Solution:

Number of times 2 heads come up = 72

Total number of times the coins were tossed = 200

, the probability of 2 heads coming up = 72/200 = 9/25

 

5. An organisation selected 2400 families at random and surveyed them to determine a relationship between income level and the number of vehicles in a family. The information gathered is listed in the table below:

Monthly income
(in ₹)
Vehicles per family
0 1 2 Above 2
Less than 7000 10 160 25 0
7000-10000 0 305 27 2
10000-13000 1 535 29 1
13000-16000 2 469 59 25
16000 or more 1 579 82 88

Suppose a family is chosen. Find the probability that the family chosen is

(i) earning ₹10000 – 13000 per month and owning exactly 2 vehicles.

(ii) earning ₹16000 or more per month and owning exactly 1 vehicle.

(iii) earning less than ₹7000 per month and does not own any vehicle.

(iv) earning ₹13000 – 16000 per month and owning more than 2 vehicles.

(v) owning not more than 1 vehicle. 

Solution:

Total number of families = 2400

(i) Number of families earning ₹10000 –13000 per month and owning exactly 2 vehicles = 29

, the probability that the family chosen is earning ₹10000 – 13000 per month and owning exactly 2 vehicles = 29/2400

(ii) Number of families earning ₹16000 or more per month and owning exactly 1 vehicle = 579

, the probability that the family chosen is earning₹16000 or more per month and owning exactly 1 vehicle = 579/2400

(iii) Number of families earning less than ₹7000 per month and does not own any vehicle = 10

, the probability that the family chosen is earning less than ₹7000 per month and does not own any vehicle = 10/2400 = 1/240

(iv) Number of families earning ₹13000-16000 per month and owning more than 2 vehicles = 25

, the probability that the family chosen is earning ₹13000 – 16000 per month and owning more than 2 vehicles = 25/2400 = 1/96

(v) Number of families owning not more than 1 vehicle = 10+160+0+305+1+535+2+469+1+579

= 2062

, the probability that the family chosen owns not more than 1 vehicle = 2062/2400 = 1031/1200

Ncert Solution For Class 9 Maths Chapter – 15  Probability

 

6. Refer to Table 14.7, Chapter 14.

(i) Find the probability that a student obtained less than 20% in the mathematics test.

(ii) Find the probability that a student obtained marks 60 or above.

Solution:

Marks Number of students
0 – 20 7
20 – 30 10
30 – 40 10
40 – 50 20
50 – 60 20
60 – 70 15
70 – above 8
Total 90

Total number of students = 90

(i) Number of students who obtained less than 20% in the mathematics test = 7

, the probability that a student obtained less than 20% in the mathematics test = 7/90

(ii) Number of students who obtained marks 60 or above = 15+8 = 23

, the probability that a student obtained marks 60 or above = 23/90

 

7. To know the opinion of the students about the subject statistics, a survey of 200 students was conducted. The data is recorded in the following table.

Opinion Number of students
like 135
dislike 65

Find the probability that a student chosen at random
(i) likes statistics, (ii) does not like it.

Solution:

Total number of students = 135+65 = 200

(i) Number of students who like statistics = 135

, the probability that a student likes statistics = 135/200 = 27/40

(ii) Number of students who do not like statistics = 65

, the probability that a student does not like statistics = 65/200 = 13/40

 

8. Refer to Q.2, Exercise 14.2. What is the empirical probability that an engineer lives:

(i) less than 7 km from her place of work?

(ii) more than or equal to 7 km from her place of work?

(iii) Within ½ km from her place of work?

Solution:

The distance (in km) of 40 engineers from their residence to their place of work were found as follows:

5     3     10     20     25     11     13     7     12     31     19     10     12     17     18      11     3     2

17   16     2     7     9     7     8      3     5     12     15     18     3    12    14     2     9     6

15     15    7     6     12

Total numbers of engineers = 40

(i) Number of engineers living less than 7 km from their place of work = 9

, the probability that an engineer lives less than 7 km from her place of work = 9/40

(ii) Number of engineers living more than or equal to 7 km from their place of work = 40-9 = 31

, probability that an engineer lives more than or equal to 7 km from her place of work = 31/40

(iii) Number of engineers living within ½ km from their place of work = 0

, the probability that an engineer lives within ½ km from her place of work = 0/40 = 0

 

 

9. Activity : Note the frequency of two-wheelers, three-wheelers and four-wheelers going past during a time interval, in front of your school gate. Find the probability that any one vehicle out of the total vehicles you have observed is a two-wheeler.

Solution:

The question is an activity to be performed by the students.

Hence, perform the activity by yourself and note down your inference.

 

10. Activity : Ask all the students in your class to write a 3-digit number. Choose any student from the room at random. What is the probability that the number written by her/him is divisible by 3? Remember that a number is divisible by 3, if the sum of its digits is divisible by 3.

Solution:

The question is an activity to be performed by the students.

Hence, perform the activity by yourself and note down your inference.

Ncert Solution For Class 9 Maths Chapter – 15  Probability

 

11. Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg):


4.97      5.05      5.08     5.03     5.00     5.06     5.08      4.98       5.04       5.07       5.00


Find the probability that any of these bags chosen at random contains more than 5 kg of flour.

Solution:

Total number of bags present = 11

Number of bags containing more than 5 kg of flour = 7

, the probability that any of the bags chosen at random contains more than 5 kg of flour = 7/11

 

12. In Q.5, Exercise 14.2, you were asked to prepare a frequency distribution table, regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12-0.16 on any of these days.


The data obtained for 30 days is as follows:
0.03      0.08      0.08      0.09      0.04      0.17      0.16      0.05      0.02      0.06      0.18      0.20      0.11      0.08      0.12      0.13      0.22      0.07      0.08      0.01      0.10      0.06      0.09      0.18      0.11      0.07      0.05      0.07      0.01      0.04

Solution:

Total number of days in which the data was recorded = 30 days

Number of days in which sulphur dioxide was present in between the interval 0.12-0.16 = 2

, the probability of the concentration of sulphur dioxide in the interval 0.12-0.16 on any of these days = 2/30 = 1/15

 

13. In Q.1, Exercise 14.2, you were asked to prepare a frequency distribution table regarding the blood groups of 30 students of a class. Use this table to determine the probability that a student of this class, selected at random, has blood group AB.
The blood groups of 30 students of Class VIII are recorded as follows:
A, B, O, O, AB, O, A, O, B, A, O, B, A, O, O, A, AB, O, A, A, O, O, AB, B, A, O, B, A, B, O.

Solution:

Total numbers of students = 30

Number of students having blood group AB = 3

, the probability that a student of this class, selected at random, has blood group AB = 3/30 = 1/10

Ncert Solution For Class 9 Maths Chapter – 15  Probability

For the Next Chapter Solution Click Below

Chapter 1 – Number System

Chapter 2 – Polynomials

Chapter 3 – Coordinate Geometry

Chapter 4 – Linear Equations in Two Variables

Chapter 5 – Euclid’s Geometry

Chapter 6 – Lines and Angles

Chapter 7 – Triangles

Chapter 8 – Quadrilaterals

Chapter 9 – Areas of Parallelograms and Triangles

Chapter 10 – Circles

Chapter 11 – Constructions

Chapter 12 – Heron’s Formula

Chapter 13 – Surface Areas and Volumes

Chapter 14 – Statistics

Chapter 15 – Probability

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